Celestial Mechanics Arnab Chowdhury October 9, 2022 0 Share Tweet Pin it Welcome to your Celestial Mechanics Simple Orbit An object is orbiting earth at a height of $100$ $km$ from the surface. What's the period in $seconds$? Gravitational Constant, $G=6.673\times10^{-11}$ $Nm^2kg^{-2}$ Mass of the Earth, $M_e = 6\times 10^{24} $ $kg $ Radius of the Earth, $R=6400$ $km$ Hint Time is Up! Time's up Previous Post Contact form Related Posts Uncategorized BDOAA 2023 February 12, 2023 Uncategorized BDOAA Winter Workshop November 5, 2022 Astronomy Ratio between the density of Dark Energy? July 24, 2022 Comments are closed.
Comments are closed.