Celestial Mechanics Arnab Chowdhury October 9, 2022 0 Share Tweet Pin it Welcome to your Celestial Mechanics Simple Orbit An object is orbiting earth at a height of $100$ $km$ from the surface. What's the period in $seconds$? Gravitational Constant, $G=6.673\times10^{-11}$ $Nm^2kg^{-2}$ Mass of the Earth, $M_e = 6\times 10^{24} $ $kg $ Radius of the Earth, $R=6400$ $km$ Hint Time is Up! Time's up Previous Post Contact form Related Posts Uncategorized BDOAA 2024 January 25, 2024 Uncategorized জ্যোতির্বৈজ্ঞানিক পরিভাষা January 6, 2024 Uncategorized BDOAA 2023 February 12, 2023 Comments are closed.
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